#905. Counting letters

when green flag clicked
set [word v] to [coconut]
set [c v] to (0)
set [i v] to (1)
repeat (length of (word))
if <(letter (i) of (word)) = [u]> then
change [c v] by (1)
end
change [i v] by (1)
end
say (c)

# When the green flag is clicked
word = "coconut"
c = 0
i = 1
for _ in range(len(str(word))):
    if (str(word))[i - 1] == "u":
        c += 1
    i += 1
print(c)

let word = 0, c = 0, i = 0;

// When the green flag is clicked
word = "coconut";
c = 0;
i = 1;
for (let j = 0; j < String(word).length; j++) {
  if ((String(word))[i - 1] === "u") {
    c += 1;
  }
  i += 1;
}
console.log(c);

💡 Not sure? Build it in Scratch and try it out.